2y^2+28y+26=0

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Solution for 2y^2+28y+26=0 equation:



2y^2+28y+26=0
a = 2; b = 28; c = +26;
Δ = b2-4ac
Δ = 282-4·2·26
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-24}{2*2}=\frac{-52}{4} =-13 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+24}{2*2}=\frac{-4}{4} =-1 $

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